# LeetCode 142. Linked List Cycle II (Medium)

## 原始问题

Given a linked list, return the node where the cycle begins. If there is no cycle, return null.

Note: Do not modify the linked list.

Can you solve it without using extra space?

## 解题思路

$$b=m+2b-NL$$
$$\Rightarrow b=NL-m$$
$$\because 0 \leqslant b \leqslant L, 0 \leqslant m \leqslant L$$
$$\therefore N = 1$$
$$\Rightarrow b=L-m$$

$$2(a+b)=a+b+KL$$

$$\Rightarrow a=KL-b$$
$$\Rightarrow a=(K-1)L+L-b$$
$$\Rightarrow a=(K-1)L+c$$